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June 2025 Algebra I Regents — Answer Key & Worked Solutions

Every question from the June 2025 Algebra I Regents exam, with the correct answer and a full step-by-step solution. Check your work, learn the method, then convert your raw score.

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These are real questions from the June 2025 Algebra I New York State Regents examination, published by NYSED. Worked solutions are written by RegentsLab.

Question 1 · 2 pts

The expression $\frac{10}{\sqrt{2}}$ is equivalent to

Worked solution
$\frac{10}{\sqrt2}\cdot\frac{\sqrt2}{\sqrt2}$ rationalize the denominator
$=\frac{10\sqrt2}{2}=5\sqrt2$
Answer: $5\sqrt{2}$

Multiplying numerator and denominator by root 2 rationalizes the denominator and simplifies to 5 root 2.

Question 2 · 2 pts

A parabola is graphed on the set of axes below. Over which interval is the parabola only increasing?

alg1 question 2 figure
Worked solution
$\text{vertex located at } x=3$
$\text{parabola opens upward} \Rightarrow \text{decreasing for } x<3, \text{ increasing for } x\ge3$
Answer: $[3,\infty)$

The graph shows the vertex at x = 3; since the parabola opens upward, the function is increasing only for x >= 3.

Question 3 · 2 pts

Which scenario represents an exponential relationship?

Worked solution
$5\%\text{ growth per month}\Rightarrow y=a(1.05)^t$ percent growth is multiplicative, i.e. exponential
Answer: Dylan hopes to grow his business by 5% each month.

A percent increase each month is multiplicative growth, the defining feature of an exponential relationship; the other three scenarios describe constant (linear) changes.

Question 4 · 2 pts

The geometry test scores for Andrea and Joe are shown in the table below. Which statement about their test scores is correct?

alg1 question 4 figure
Worked solution
$\bar{x}_{Andrea}=\frac{82+87+90+84}{4}=85.75$
$\bar{x}_{Joe}=\frac{91+78+94+67}{4}=82.5$
$\text{Andrea's scores (82-90) are tightly clustered; Joe's scores (67-94) are widely spread}$
Answer: The mean of Andrea's test scores is higher than Joe's, but Joe's standard deviation is higher than Andrea's.

Andrea's mean (85.75) is higher than Joe's (82.5), but Joe's scores are much more spread out, giving Joe a higher standard deviation.

Question 5 · 2 pts

Which polynomial has a degree of 3 and a leading coefficient of 2?

Worked solution
$2x^3+x^2+4x$ highest-power term is 2x^3: degree 3, leading coefficient 2
Answer: $2x^3+x^2+4x$

2x^3+x^2+4x has degree 3 (highest exponent) and leading coefficient 2 (coefficient of the x^3 term).

Question 6 · 2 pts

The expression $(-3x^2+9)-(7x^2-5x+4)$ is equivalent to

Worked solution
$(-3x^2+9)-(7x^2-5x+4)$
$=-3x^2+9-7x^2+5x-4$
$=-10x^2+5x+5$
Answer: $-10x^2+5x+5$

Distribute the negative sign across the second polynomial, then combine like terms.

Question 7 · 2 pts

The function h(x) is used to calculate the average height, in inches, of a tomato plant x weeks after it is transplanted. These data are represented in the table below. Between weeks 4 and 12, the average rate of change, in inches per week, is

alg1 question 7 figure
Worked solution
$\frac{h(12)-h(4)}{12-4}=\frac{60-12}{8}=\frac{48}{8}=6$
Answer: $6$

Average rate of change is the change in height divided by the change in weeks, from week 4 to week 12.

Question 8 · 2 pts

Chloe is solving the equation $x^2+5x=3x+3$. Her first step is shown below. Given: $x^2+5x=3x+3$ Step 1: $x^2+2x-3=0$ Which property justifies this step?

Worked solution
$x^2+5x=3x+3$
$x^2+5x-3x-3=0 \Rightarrow x^2+2x-3=0$
Answer: the subtraction property of equality

Both 3x and 3 were subtracted from each side of the equation, which is the subtraction property of equality.

Question 9 · 2 pts

Which function represents the graph of $w(x) = |x|$ shifted 2 units to the right?

Worked solution
$w(x)=|x| \rightarrow h(x)=|x-2|$ replace x with (x-2) for a rightward shift
Answer: $h(x) = |x-2|$

Shifting a graph to the right replaces x with (x - 2), giving h(x) = $|x - 2|$.

Question 10 · 2 pts

Given the system of equations: $y + 4x = 5$ $2x - 3y = 10$ A step in solving this system by using the substitution method would be

Worked solution
$y+4x=5 \Rightarrow y=5-4x$
$2x-3(5-4x)=10$
Answer: $2x - 3(5 - 4x) = 10$

Solving the first equation for y gives y = 5 - 4x; substituting into the second equation gives 2x - 3(5 - 4x) = 10.

Question 11 · 2 pts

Which equation is equivalent to $x^2 - 6x = 27$?

Worked solution
$x^2-6x=27$
$x^2-6x+9=27+9$ add (b/2)^2 = 9 to both sides
$(x-3)^2=27+9$
Answer: $(x-3)^2 = 27 + 9$

Completing the square requires adding (b/2)^2 = 9 to both sides, giving (x-3)^2 = 27 + 9.

Question 12 · 2 pts

The box plots below summarize the ages of athletes on the swim team and the track team. Based on the box plots, which statement must be true?

alg1 question 12 figure
Worked solution
$IQR_{swim} \approx 15-12=3$
$IQR_{track} \approx 13-10=3$
Answer: The IQR of both teams is the same.

Both box plots show an IQR (distance from Q1 to Q3) of about 3 years, so the IQR of both teams is the same.

Question 13 · 2 pts

The graph of f(x) is shown below. The domain of this function is

alg1 question 13 figure
Worked solution
$\text{open circle at } x=0,\ \text{closed dot at } x=12$
$\text{domain}=0<x\le12$
Answer: $0 < x \le 12$

The graph starts with an open circle at x = 0 (excluded) and ends with a closed point at x = 12 (included), so the domain is 0 < x <= 12.

Question 14 · 2 pts

The sum of 3 and $\sqrt{5}$ is

Worked solution
$3+\sqrt5$ rational + irrational = irrational
Answer: irrational, since the sum cannot be expressed as a terminating or repeating decimal

Root 5 is irrational, and a rational number plus an irrational number is always irrational; irrational numbers cannot be written as terminating or repeating decimals.

Question 15 · 2 pts

Which expression is equivalent to $a^8 - b^6$?

Worked solution
$a^8-b^6=(a^4)^2-(b^3)^2$
Answer: $(a^4)^2-(b^3)^2$

a^8 = (a^4)^2 and b^6 = (b^3)^2, so a^8 - b^6 = (a^4)^2 - (b^3)^2.

Question 16 · 2 pts

The sum of $2\sqrt{27}$ and $4\sqrt{12}$ is

Worked solution
$2\sqrt{27}=2\sqrt{9\cdot3}=2(3\sqrt3)=6\sqrt3$
$4\sqrt{12}=4\sqrt{4\cdot3}=4(2\sqrt3)=8\sqrt3$
$6\sqrt3+8\sqrt3=14\sqrt3$
Answer: $14\sqrt{3}$

Simplify each radical to like terms of root 3, then add the coefficients.

Question 17 · 2 pts

The sum of Tim's age and Jack's age is 44. Tim's age is 4 less than 7 times Jack's age, x. An equation that could be used to model this scenario is

Worked solution
$\text{Tim}=7x-4,\ \text{Jack}=x$
$(7x-4)+x=44$
Answer: $(7x - 4) + x = 44$

Tim's age is (7x - 4) and Jack's age is x; their sum equals 44.

Question 18 · 2 pts

Given the function $g(x) = \frac{2^{x+3}}{x^2-2}$, what is the value of $g(-2)$?

Worked solution
$g(-2)=\frac{2^{-2+3}}{(-2)^2-2}=\frac{2^1}{4-2}=\frac{2}{2}=1$
Answer: $1$

Substitute x = -2 into the function and simplify.

Question 19 · 2 pts

Four graphs are shown below, labeled A, B, C, and D. Which of the graphs represent(s) a function?

alg1 question 19 figure
Worked solution
$\text{Vertical line test: A and B pass; C and D fail}$
Answer: A and B, only

Graph A (a single curve) and graph B (a single horizontal line) each pass the vertical line test; graph C (a single vertical line) and graph D (a circle) do not.

Question 20 · 2 pts

The formula to calculate kinetic energy is $K = \frac{1}{2}mv^2$, where K is kinetic energy, m is mass, and v is velocity. When m is written in terms of K and v, the equation is

Worked solution
$K=\frac12mv^2$
$2K=mv^2$
$m=\frac{2K}{v^2}$
Answer: $m = \frac{2K}{v^2}$

Multiply both sides by 2 and divide by v^2 to isolate m.

Question 21 · 2 pts

The solution to the equation $\frac{2(3x-1)}{3} = x + 2$ is

Worked solution
$\frac{2(3x-1)}{3}=x+2$
$2(3x-1)=3(x+2)$
$6x-2=3x+6$
$3x=8 \Rightarrow x=\frac83$
Answer: $\frac{8}{3}$

Clear the fraction by multiplying both sides by 3, then solve the resulting linear equation.

Question 22 · 2 pts

Which equation represents the sequence 12, 6, 3, $\frac{3}{2}$, ..., where $a_1 = 12$?

Worked solution
$r=\frac{6}{12}=\frac12$
$a_n=12\cdot\left(\frac12\right)^{n-1}$
Answer: $a_n = 12\cdot\left(\frac{1}{2}\right)^{n-1}$

Each term is half the previous term, so the common ratio is 1/2 and a1 = 12.

Question 23 · 2 pts

The axis of symmetry is x = 2 for which quadratic function?

alg1 question 23 figure
Worked solution
$h(x)=x^2-4x-5$
$x=-\frac{b}{2a}=-\frac{-4}{2(1)}=2$
Answer: $h(x) = x^2 - 4x - 5$

For h(x) = x^2 - 4x - 5, the axis of symmetry is x = -b/2a = 2. The graph (choice 1) appears to have vertex near x = 1; j(x) has axis x = -2; the table (choice 3) is symmetric about x = 0.

Question 24 · 2 pts

Each day, a freight train passes by Anna's house. This freight train travels at 49 miles per hour. Each railroad car is 56 feet long. Which expression represents the number of railroad cars that pass by Anna's house per minute?

Worked solution
$\text{mi}\cdot\frac{\text{ft}}{\text{mi}}\cdot\frac{\text{hr}}{\text{min}}\cdot\frac{\text{car}}{\text{ft}} = \frac{\text{car}}{\text{min}}$ units must cancel to cars per minute
Answer: $\frac{49\text{ mi}}{1\text{ hr}}\cdot\frac{5280\text{ ft}}{1\text{ mi}}\cdot\frac{1\text{ hr}}{60\text{ min}}\cdot\frac{1\text{ car}}{56\text{ ft}}$

Units must cancel correctly: miles cancel with miles (5280 ft/mi, not inverted), and hours cancel with hours (1 hr/60 min, not inverted), leaving cars per minute; only choice (3) sets up all conversion factors so the units cancel properly.

Question 25 · 2 pts · constructed response

A survey was taken to determine whether students preferred to watch videos or listen to music. Of the 100 students surveyed, 44 were seniors. Of the 65 students who preferred to watch videos, 42 were juniors. Use this information to complete a frequency table with rows Watch Videos, Listen to Music, and Total, and columns Juniors, Seniors, and Total.

alg1 question 25 figure
Model answer: Watch Videos: 42 Juniors, 23 Seniors, 65 Total. Listen to Music: 14 Juniors, 21 Seniors, 35 Total. Total: 56 Juniors, 44 Seniors, 100 Total.
Worked solution
$\text{Total juniors}=100-44=56$
$\text{Watch videos, seniors}=65-42=23$
$\text{Listen to music, juniors}=56-42=14$
$\text{Listen to music, seniors}=44-23=21$
$\text{Listen to music total}=14+21=35$
Answer: Watch Videos: 42 Juniors, 23 Seniors, 65 Total. Listen to Music: 14 Juniors, 21 Seniors, 35 Total. Total: 56 Juniors, 44 Seniors, 100 Total.

Use the total of 100 students and 44 seniors to find 56 juniors, then subtract the given cell values from the row and column totals to fill in the rest of the two-way frequency table.

Question 26 · 2 pts · constructed response

Solve the inequality for y: $5(2-y) > -11y-8$

Model answer: $y > -3$
Worked solution
$5(2-y)>-11y-8$
$10-5y>-11y-8$
$10-5y+11y>-8$
$10+6y>-8$
$6y>-18$
$y>-3$
Answer: $y > -3$

Distribute the 5, collect the y-terms on one side, and divide by a positive coefficient (6) to isolate y (no need to flip the inequality since dividing by a positive number).

Question 27 · 2 pts · constructed response

Express $(5x-3)(-2x+7)$ as a trinomial in standard form.

Model answer: $-10x^2+41x-21$
Worked solution
$(5x-3)(-2x+7)$
$=5x(-2x)+5x(7)+(-3)(-2x)+(-3)(7)$
$=-10x^2+35x+6x-21$
$=-10x^2+41x-21$
Answer: $-10x^2+41x-21$

Use the distributive property (FOIL) to multiply the two binomials, then combine the like x-terms.

Question 28 · 2 pts · constructed response

The first and fourth terms in an arithmetic sequence are given below. $-20, \_\_\_\_, \_\_\_\_, -2$ Determine the eighth term.

Model answer: $a_8 = 22$
Worked solution
$d=\frac{a_4-a_1}{3}=\frac{-2-(-20)}{3}=\frac{18}{3}=6$
$a_8=a_1+7d=-20+7(6)=-20+42=22$
Answer: $a_8 = 22$

Find the common difference using the first and fourth terms (three intervals apart), then use it to extend the sequence to the eighth term.

Question 29 · 2 pts · constructed response

Write an equation in slope-intercept form for the line that passes through $(-2,5)$ and has a slope of $-3$.

alg1 question 29 figure
Model answer: $y = -3x - 1$
Worked solution
$y-5=-3(x-(-2))$
$y-5=-3(x+2)$
$y-5=-3x-6$
$y=-3x-1$
Answer: $y = -3x - 1$

Use point-slope form with the given point and slope, then solve for y to get slope-intercept form.

Question 30 · 2 pts · constructed response

Factor the expression $x^3 - 36x$ completely.

Model answer: $x(x-6)(x+6)$
Worked solution
$x^3-36x=x(x^2-36)$ factor out the GCF, x
$=x(x-6)(x+6)$ difference of squares
Answer: $x(x-6)(x+6)$

Factor out the GCF x, then factor the resulting difference of squares x^2 - 36.

Question 31 · 4 pts · constructed response

Graph $f(x) = -3x$ and $g(x) = x^2 + 2$ on the set of axes below. State the values of x that satisfy the equation $f(x) = g(x)$.

alg1 question 31 figure
Model answer: $x = -1$ and $x = -2$
Worked solution
$f(x)=g(x)$
$-3x=x^2+2$
$0=x^2+3x+2$
$0=(x+1)(x+2)$
$x=-1 \text{ or } x=-2$
Answer: $x = -1$ and $x = -2$

Set the linear and quadratic expressions equal, solve the resulting quadratic by factoring; the graphs of the line and parabola intersect at these two x-values (at points (-1,3) and (-2,6)).

Question 32 · 4 pts · constructed response

Using the quadratic formula, solve $6x^2 + 2x - 1 = 0$. Express the answer in simplest radical form.

Model answer: $x = \frac{-1\pm\sqrt{7}}{6}$
Worked solution
$6x^2+2x-1=0,\ a=6,\ b=2,\ c=-1$
$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-2\pm\sqrt{4+24}}{12}$
$=\frac{-2\pm\sqrt{28}}{12}=\frac{-2\pm2\sqrt7}{12}$
$=\frac{-1\pm\sqrt7}{6}$
Answer: $x = \frac{-1\pm\sqrt{7}}{6}$

Substitute a, b, c into the quadratic formula, simplify the radical (root 28 = 2 root 7), then reduce the resulting fraction to simplest radical form.

Question 33 · 4 pts · constructed response

The table below shows the price of a new cell phone and the length of time, in months, since its release. Time Since Release, in Months (x): 0, 3, 6, 9, 12 Price, in Dollars (y): 1200, 1150, 1100, 1000, 920 State the linear regression equation for this set of data. Round all values to the nearest hundredth. State the correlation coefficient for this data set, to the nearest hundredth. State what the correlation coefficient indicates about the linear fit of the data.

alg1 question 33 figure
Model answer: $y = -23.67x + 1216.00$; $r \approx -0.99$; this indicates a strong, negative linear correlation, meaning the linear regression model fits the data very well.
Worked solution
$\bar x=6,\ \bar y=1074$
$S_{xy}=\sum(x-\bar x)(y-\bar y)=-2130,\quad S_{xx}=\sum(x-\bar x)^2=90$
$b=\frac{S_{xy}}{S_{xx}}=\frac{-2130}{90}\approx-23.67$
$a=\bar y-b\bar x=1074-(-23.67)(6)\approx1216.00$
$y=-23.67x+1216.00$
$S_{yy}=\sum(y-\bar y)^2=51520$
$r=\frac{S_{xy}}{\sqrt{S_{xx}S_{yy}}}=\frac{-2130}{\sqrt{90\cdot51520}}\approx-0.99$
Answer: $y = -23.67x + 1216.00$; $r \approx -0.99$; this indicates a strong, negative linear correlation, meaning the linear regression model fits the data very well.

Using linear regression (by calculator or by-hand least squares) on the five data points gives slope of about -23.67 and y-intercept of about 1216.00. The correlation coefficient of about -0.99 shows a strong negative linear correlation, meaning the linear model is an excellent fit (price decreases steadily and predictably over time).

Question 34 · 4 pts · constructed response

Solve the following system of equations algebraically for all values of x and y. $y = x^2 + 9x + 4$ $y - 2x = -6$

Model answer: $(x,y) = (-5,-16)$ and $(x,y) = (-2,-10)$
Worked solution
$y-2x=-6 \Rightarrow y=2x-6$
$2x-6=x^2+9x+4$
$0=x^2+7x+10$
$0=(x+5)(x+2)$
$x=-5 \text{ or } x=-2$
$x=-5:\ y=2(-5)-6=-16$
$x=-2:\ y=2(-2)-6=-10$
Answer: $(x,y) = (-5,-16)$ and $(x,y) = (-2,-10)$

Solve the linear equation for y, substitute into the quadratic equation, solve the resulting quadratic by factoring, then back-substitute each x-value to find the corresponding y-value.

Question 35 · 6 pts · constructed response

Sarah earns $6 per hour babysitting and $12 per hour tutoring. Her goal is to earn at least $120 per week. Sarah is allowed to work a maximum of 14 hours per week doing both jobs. If x represents the number of hours Sarah babysits and y represents the number of hours she tutors, write a system of inequalities that could model this situation. On the set of axes below, graph the system of inequalities that you wrote. State a combination of hours babysitting and tutoring that would satisfy this situation. Justify your answer.

alg1 question 35 figure
Model answer: System: $6x + 12y \ge 120$ and $x + y \le 14$ (with $x \ge 0,\ y \ge 0$). Example solution satisfying the system: $x = 0$ hours babysitting, $y = 10$ hours tutoring.
Worked solution
$6x+12y\ge120$ earns at least $120 total
$x+y\le14$ works at most 14 hours total
$x\ge0,\ y\ge0$ hours cannot be negative
$\text{Test }(x,y)=(0,10):\ 6(0)+12(10)=120\ge120\ \checkmark,\quad 0+10=10\le14\ \checkmark$
Answer: System: $6x + 12y \ge 120$ and $x + y \le 14$ (with $x \ge 0,\ y \ge 0$). Example solution satisfying the system: $x = 0$ hours babysitting, $y = 10$ hours tutoring.

Translate the earning goal and the hour limit into two inequalities and graph their overlapping (feasible) region on the given axes. Any point in that shaded region works; for example, 0 hours babysitting and 10 hours tutoring earns exactly $120 while using only 10 of the allowed 14 hours, satisfying both constraints.

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